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Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182, = 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;
For two half lives, t = 2 ×
∴ t = 2 × 15 = 30
∴ The amount left, N(t) = 0.75 grams
Answer:
2445 L
Explanation:
Given:
Pressure = 1.60 atm
Temperature = 298 K
Volume = ?
n = 160 mol
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 08206 L.atm/K.mol
Applying the equation as:
1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K
<u>⇒V = 2445.39 L</u>
Answer to four significant digits, Volume = 2445 L
Answer:
Initial concentration of HI is 5 mol/L.
The concentration of HI after is 0.00345 mol/L.
Explanation:
Rate Law:
Rate constant of the reaction = k =
Order of the reaction = 2
Initial rate of reaction =
Initial concentration of HI =
Final concentration of HI after t = [A]
t =
Integrated rate law for second order kinetics is given by:
The concentration of HI after is 0.00345 mol/L.