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ira [324]
3 years ago
10

Please help, last two questions.

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0
First problem.
The function is f(x) = 3^x.
The base, b, is 3 since 3 is raised to power x.
The question is what value of x used in 3^x makes the expression 3^x equal to 3?
Look at the graph, and find the point that has y-value 3.
Which x-value does that point have?
The point is (1, 3), and the x-value is 1.

Second question.
The question is similar to the question above using a different exponential function.
(1/4)^1 = 1/4, so the answer is x = 1
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What the improper fraction of 9 1/3
kherson [118]

Answer:

The improper fraction of 9 1/3 is 28/3

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2 years ago
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Y=-4x+6<br> Find an equation for the inverse relation
kherson [118]

Answer:

Step-by-step explanation:

y = -4x + 6.....switch x and y and solve for y

x = -4y + 6 ....subtract 6 from both sides

x - 6 = -4y....divide by -4 on both sides

(x - 6) / -4 = y or y = -1/4x + 3/2 <====

3 0
3 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
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Find the equation of the line that passes through points A and B.<br> y<br> X A (4, 7)<br> B (2, 3)
g100num [7]

Answer:

y = 2x - 1.

Step-by-step explanation:

The slope = (7-3)/(4-2)

= 4/2

= 2.

y - y1 = m(x - x1)

Here m = 2 , x1 = 2 and y1 = 3. So we have:

y - 3 = 2(x - 2)

y = 2x - 4 + 3

y = 2x - 1.

We have used the point (2, 3) to find the equation but we could have used (4, 7). We would have got the same answer.

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3 years ago
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svetlana [45]
I am not so sure, maybe D. Translation. Don't depend on my answer because I am not very sure

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3 years ago
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