Answer:
x=2.5&.5
Step-by-step explanation:
The quadratic formula is (-b+or-sqrt(b^2-4ac)/2a
12+or-sqrt((-12^2)-4(4)(5))
12+or-sqrt(144-80)
12+or-sqrt(64)
(12+8)/8 and (12-8)/8
x=2.5 and x=.5
{ y = 3 x - 4
9x -3y = 14
Subsititute y = 3x-4 :
[ 9 x - 3 ( 3 x-14 )=14]
Refine:
9 x - 3 ( 3 x - 4 ) = 14
- 2 = 0
is false , therefore the system of equations has no solution
Answer A
hope this helps!
8 groups is what i suppose
Hope this helps!!! ;-)
Option A: z + 1
Option B: 6 + w
Option D: 
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C: ![y^{2}-\sqrt[3]{y}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4)
![y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4](https://tex.z-dn.net/?f=y%5E%7B2%7D-%5Csqrt%5B3%5D%7By%7D%2B4%3Dy%5E%7B2%7D-%7By%7D%5E%7B1%2F3%7D%2B4)
Here, y have fractional exponent.
So, it is not a polynomial.
Option D: 
By the definition,
is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and
are polynomials.
Answer:
The answer should be choice D.
HOPE THIS HELPS! :)