Question

in an abc triangle, the hypotenuse is 10 and the other sides are x, the measurement of angle B is 90 deg, what is the value of x

Answer 1

Answer:

x = $5\sqrt{2}$.

Step-by-step explanation:

The question says that the hypotenuse is 10, while the other two sides are both x. That means that the triangle is a 45-45-90 angle.

Because this is a 45-45-90 triangle, the proportions of the side lengths are 1-1-sqrt(2).

Since the hypotenuse is 10, and the side length is x, we can make a proportion.

$\frac{10}{\sqrt{2}} =\frac{x}{1}$

$x\sqrt{2}$ = 10

x = $\frac{10}{\sqrt{2} }$

x = $\frac{10 * (\sqrt{2} )}{(\sqrt{2})(\sqrt{2} ) }$

x = $\frac{10\sqrt{2} }{2}$

x = $5\sqrt{2}$

Hope this helps!