All categories

2 years ago

Select the expression that has a sum of 75/100

Mathematics

1 answer:

umka21 [38]2 years ago

3 0

Answer:

See below

Step-by-step explanation:

70/100 + 4/10 is equivalent to 70/100 + 40/100 which equals 110/100.

68/100 + 6/10 is equivalent to 68/100 + 60/100 which equals 128/100.

6/10 + 12/100 is equivalent to 60/100 + 12/100 which equals 72/100.

4/10 + 34/100 is equivalent to 40/100 + 34/100 which equals 74/100.

None of them equal 75/100, however if you were looking for 74/100 or 72/100, check above.

You might be interested in

PLEASE IM BEGGING! HELP!

user100 [1]

Answer:

Part A: after 9 days the radius of the algae would be 12.81mm so the domain is 9. you would plot the domain at (0,9)

Part B: the y-intercept (the 9) represents the amount of algae the experiment started off with.

Part C: the rate of change is 0.

Step-by-step explanation:

4 0

3 years ago

(a^3)^6 = (a^2)^x what is x?

alexgriva [62]

Answer:

Step-by-step explanation:

Solution

Here,

(a^3)^6=(a^2)^x

or, a^18=a^2x

or, 18=2x

or, x=18/2

x=9

8 0

3 years ago

Quadratic shifted left by 1 unit vertical stretch by a factor of 1.

Aleksandr [31]

Answer:

1(x+1)^2

Step-by-step explanation:

8 0

3 years ago

One watering system needs about three times as long to complete a job as another warning system when both systems operate at the

algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = $3x$

Rate to complete the job by another watering system = $\frac{1}{x}\ job/min$

Rate to complete the job by One watering system = $\frac{1}{3x}\ job/min$

Rate at which both can complete the job = $\frac{1}{9}\ job/min$

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

$\frac{1}{x}+\frac{1}{3x}=\frac19$

Now taking LCM to make the denominator common we get;

$\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}$

By Cross multiplication we get;

$4\times9 =3x\\\\3x =36$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min$

Time required by One watering system = $3x =3\times 12 =36\ min$

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

6 0

3 years ago

C=5/9(F-32) solve for F

mina [271]

F= 9/5 C + 32
or
F= 9/5(C+32)
 Hoped this helped:)

7 0

2 years ago