<span>sin(theta) = 6/10 and theta is in the second quadrant. Use trigonometric identities to find the following quantities exactly.
---
sin = 3/5
=============
(a) cos(theta)
cos = sqrt(1 - sin^2) = -4/5 (negative in Q2)
-----
(b) sin(2theta) =
sin(2t) = 2sin(t)*cos(t) = -24/25 --> Q3
-----
(c) cos(2theta
cos(2t) = sqrt(1 - sin^2(2t)) = -7/25 (negative in Q3)
-----
(d) tan(2theta) = = sin(2t)/cos(2t) = 24/7 (+ in Q3)</span>
What you have to do is use sin^-1 (8192)=x. Then you should get a decimal and you can round it
Ok, 1 bionimial theorem coming right up
for a binomial expansion of (a+b)^n
the kth term is
means
n is 5
4th term
4-1=3
and a=2x
b=5
so
(10)(4x^2)(125)
5000x^2 is the 4th term
The answer is 10 u have to put 2/3 multiplied by 15/1
Answer:
See below in bold.
Step-by-step explanation:
(-3)^3(2^6)/(-3)^5(2)^2
= (-3)^(3-5)*(2^4)
= 2^4 / (-3)^2 so a = 4 and b = 2.
2^4 / (-3)^2
= 16/9 so c = 16 and d = 9.
