Question

(-3)^3(2^6)/(-3)^5(2)^2=(2)^a/(-3)^b=c/d What are the values of a,b,c,and d

Answer 1

Answer:

See below in bold.

Step-by-step explanation:

(-3)^3(2^6)/(-3)^5(2)^2

= (-3)^(3-5)*(2^4)

= 2^4 / (-3)^2   so  a = 4 and b = 2.

2^4 / (-3)^2

= 16/9    so c = 16 and d = 9.