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lisov135 [29]
3 years ago
9

(-3)^3(2^6)/(-3)^5(2)^2=(2)^a/(-3)^b=c/d What are the values of a,b,c,and d

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

See below in bold.

Step-by-step explanation:

(-3)^3(2^6)/(-3)^5(2)^2

= (-3)^(3-5)*(2^4)

= 2^4 / (-3)^2   so  a = 4 and b = 2.

2^4 / (-3)^2

= 16/9    so c = 16 and d = 9.

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