Answer:
P generation: 1 purple flower (AA) : 1 white flower (aa)
F1 generation: 4 purple flowers (Aa) : 0 white flowers
F2 generation: 3 purple flowers (AA, Aa) : 1 white flower
Explanation:
Assuming the parents are AA and aa, the allele for white flowers is recessive, so there needs to be two of them for the trait to be expressed. Thus, the capital A purple allele that the other parent contributes will mask that white allele and all the flowers will appear purple. However, all of the offspring are Aa now, so when they are crossed, there's a 25% chance that they'll both contribute the lowercase a allele that codes for white flowers. Remember that if both of them give the lowercase a allele then the offspring will be aa and appear white.
I'm not exactly sure, but i would guess the noble gasses. The reason for this is that the noble gasses are stable. There outer shells are completely full. That means they have the same number of electrons.
The answer is b
Because it makes sense
Non-disjunction occurred during meiosis II in the maternal germinal line. Non-disjunction may occur during meiosis I or meiosis II.
<h3>What is non-disjunction?</h3>
Non-disjunction refers to the phenomena where homo-logous chromosomes or sister chromatids are not separated properly during cell division.
Non-disjunction during meiosis II is due to the failure of the sister chromatids to separate during Anaphase II.
In this case, the genotype of the father is 5/8, thereby transmitting alleles number 5 and 8.
Moreover, the genotype of the mother is 6/3, thereby she is able to transmit alleles number 6 and 3.
Learn more about non-disjunction here:
brainly.com/question/1274629
