Answer:
b
Step-by-step explanation:
i did the math for over an hour and got the same answer 25 times
Answer:
Step-by-step explanation:
You basicly want to use A=pe^rt to find the amount of money you now have. A is the total amount of money you have after a certian period of time (T) while your money grows at a steady rate (R). (E) is an irrational number 2.71828. (P) is the amount of money you started with. Your precentage is your rate and this means you earn 9% of what you have per year. The way the problem would be set up A=1500(2.71828)^(.09)(2). This problem allows for exponential growth to occur because your two variables are time and the amount you have in that time.
![x(t)=\int_0^6(2*e^ \frac{t}{2}-6})\ dt=\left[4*e^ \frac{t}{2}-6t\right]_0^6\\\\ =e^3-36-4=4e^3-40\approx{40.3421...}\\\\](https://tex.z-dn.net/?f=x%28t%29%3D%5Cint_0%5E6%282%2Ae%5E%20%5Cfrac%7Bt%7D%7B2%7D-6%7D%29%5C%20dt%3D%5Cleft%5B4%2Ae%5E%20%5Cfrac%7Bt%7D%7B2%7D-6t%5Cright%5D_0%5E6%5C%5C%5C%5C%20%3De%5E3-36-4%3D4e%5E3-40%5Capprox%7B40.3421...%7D%5C%5C%5C%5C)
