Answer:
-18k^2+72kx+54x^2
Step-by-step explanation:
Sorry i don't have the step-by-step but that's the answer
Ain’t really sure but I’m it’s ( C
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4
