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coldgirl [10]
3 years ago
8

Show solution of the ratio of 14 days to 3 weeks in simplest form?

Mathematics
2 answers:
Paladinen [302]3 years ago
5 0

Answer:

2:3

Step-by-step explanation:

We are asked to find the ratio 14 days to 3 weeks in simplest form.

We know that 1 week equals 7 days, so 3 weeks will be equal to 21 (3*7) days.

So our ratio would be 14:21.

We can see that 14 and 21 share a common factor 7.

14:21=7\cdot2:7\cdot3=2:3

Therefore, our required ratio would be 2:3.

erica [24]3 years ago
4 0
14:3 can be written as 14/3...and this does not simplify

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Answer:

Null hypothesis:\mu \geq 7.3    

Alternative hypothesis:\mu < 7.3    

z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235    

p_v =P(z    

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.  

Step-by-step explanation:

1) Data given and notation    

\bar X=7.2 represent the sample mean    

\sigma=0.81 represent the population standard deviation    

n=100 sample size    

\mu_o =7.3 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean pressure is lower than the specificated value 7.3, the system of hypothesis are :    

Null hypothesis:\mu \geq 7.3    

Alternative hypothesis:\mu < 7.3    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235    

4) P-value    

Since is a one-side lower test the p value would given by:    

p_v =P(z    

5) Conclusion    

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.  

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