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klemol [59]
3 years ago
8

Which five statements about hemoglobin and myoglobin structure are true? Each iron atom can form six coordination bonds. One of

these bonds is formed between iron and oxygen. By itself, heme is not a good oxygen carrier. It must be part of a larger protein to prevent oxidation of the iron atom. Molecular oxygen binds irreversibly to Fe2+ in heme. Heme is composed of an organic protoporphyrin component and a metal atom. Hemoglobin and myoglobin are heterotetramers. Both hemoglobin and myoglobin contain a prosthetic group called heme, which contains a central iron atom. Each hemoglobin molecule can bind four oxygen molecules; each myoglobin can bind only one oxygen molecule.
Chemistry
2 answers:
Ulleksa [173]3 years ago
7 0

Answer:

Here's what I get  

Explanation:

Each iron atom can form six coordination bonds. One of these bonds is formed between iron and oxygen.  

TRUE

By itself, heme is not a good oxygen carrier. It must be part of a larger protein to prevent oxidation of the iron atom.  

TRUE

Molecular oxygen binds irreversibly to Fe²⁺ in heme.  

False. It binds reversibly with heme.

Heme is composed of an organic protoporphyrin component and a metal atom.  

TRUE

Hemoglobin and myoglobin are heterotetramers.

False. Hemoglobin is a tetramer. Myoglobin a monomeric protein.

Both hemoglobin and myoglobin contain a prosthetic group called heme, which contains a central iron atom.

TRUE

Each hemoglobin molecule can bind four oxygen molecules; each myoglobin can bind only one oxygen molecule.

TRUE

____ [38]3 years ago
6 0

Answer:

1.  Each iron atom can form six coordination bonds. One of these bonds is formed between iron and oxygen

2.By itself heme is not a good oxygen carrier. It must be part of a larger protein to prevent oxidation of the iron atom.

3.Each hemoglobin molecule can bind four oxygen molecules; each myoglobin can bind only one oxygen molecule.

4. Heme is composed of an organic protoporphyrin component and a metal atom.

5.  Both hemoglobin and myoglobin contain a prosthetic group called heme, which contains a central iron atom.

Explanation:

Myoglobin is a protein that is muscle tissues, it functions as an oxygen storage unit. Hemoglobin is found in the fed blood dells, it functions as an oxygen transporter. It transport oxygen from the lungs to the rest of the body.

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Explain how a redox reacation involves electrons in the same way that a neutralization reaction involves protons
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For the neutralization process: an acid acts as a donor and donates protons to the base. On the other hand, the base acts as an acceptor and accepts the transferred protons. In a nutshell, neutralization is mainly proton transfer process.

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What else is produced during the combustion of butane, C4H10?<br><br> 2C4H10 + 13O2 → <br> + 10H2O
Neko [114]
<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

  • Butane, C₄H₁₀
  • Butane is a hydrocarbon in the homologous series known as alkane.

We are required to determine the other product produced in the combustion of butane apart from water.

  • We know that the complete combustion of alkane yields carbon dioxide and water.
  • Therefore, combustion of butane will yield carbon dioxide and water.
  • The balanced equation for the complete combustion of butane will be;

       2C₄H₁₀ + 13O₂ →  8CO₂ + 10H₂O

8 0
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Naturally occurring gallium is a mixture of isotopes
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What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances
belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope                    mass amu        Relative abundance

1                                77.9                     14.4

2                               81.9                     14.3

3                               85.9                      71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9  

% abundance of isotope 1 = 14.4% = \frac{14.4}{100}=0.144

Mass of isotope 2 = 81.9

% abundance of isotope 2 = 14.3% = \frac{14.3}{100}=0.143

Mass of isotope 3 = 85.9

% abundance of isotope 2 = 71.3% = \frac{71.3}{100}=0.713

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]

A=84.2amu

Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu

4 0
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