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OLEGan [10]
3 years ago
5

In ___, each of the bulbs would be Set up in paths independent and complete.

Chemistry
1 answer:
Luda [366]3 years ago
8 0

Answer:

Parallel Circuits

Explanation:

An electric circuit refers to a continuous and an interrupted pathway along which electric current can flow. A simple electrical circuit is made up of three components: the power source, two conducting wires (one at each end/terminal of the cell), and a small lamp powered by the cell. If any of the wires at the terminal is disconnected, the circuit stops working.

There are 2 types of electrical circuits, they are:

I. Series circuit

II. Parallel circuit

In a series circuit, the components are connected in such a way that the current that flows through every component is identical, and the voltage of the circuit is the sum of the voltages across every component. In a series circuit all components must function for the circuit to be complete and if any component stops functioning, the circuit stops functioning. <u>Hence, the setup path of bulbs in the series circuit is </u><u>not</u><u> independent and complete</u>

In a parallel circuits, the components are connected in such a way that all the bulbs have their own circuit. The current that flows through every circuit is dependent on the components in that circuit and so also the voltage. The result is that if any bulb burns out, all the other bulbs will continue to function. <u>We therefore conclude that the setup path of bulbs in the series circuit </u><u>is</u><u> independent and complete</u>

<u />

Hence, "In <u>parallel circuits</u>, each of the bulbs would be  set up in paths independent and complete."

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Explanation:

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What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze
enyata [817]

Answer : 17.12 g

Explanation:\Delta T =k_b\times m

\Delta T = elevation in boiling point

k_b = boiling point elevation constant

m= molality

molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}

given \Delta T=6.28^{\circ}C

Molar mass of solute = 46.0 gmol^{-1}

Weight of the solvent = 150.0 g = 0.15 kg

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molality=\frac{x}{46gmol^{-1}\times0.15kg}

6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}

x = 17.12 g



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Explanation:

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