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OLEGan [10]
3 years ago
5

In ___, each of the bulbs would be Set up in paths independent and complete.

Chemistry
1 answer:
Luda [366]3 years ago
8 0

Answer:

Parallel Circuits

Explanation:

An electric circuit refers to a continuous and an interrupted pathway along which electric current can flow. A simple electrical circuit is made up of three components: the power source, two conducting wires (one at each end/terminal of the cell), and a small lamp powered by the cell. If any of the wires at the terminal is disconnected, the circuit stops working.

There are 2 types of electrical circuits, they are:

I. Series circuit

II. Parallel circuit

In a series circuit, the components are connected in such a way that the current that flows through every component is identical, and the voltage of the circuit is the sum of the voltages across every component. In a series circuit all components must function for the circuit to be complete and if any component stops functioning, the circuit stops functioning. <u>Hence, the setup path of bulbs in the series circuit is </u><u>not</u><u> independent and complete</u>

In a parallel circuits, the components are connected in such a way that all the bulbs have their own circuit. The current that flows through every circuit is dependent on the components in that circuit and so also the voltage. The result is that if any bulb burns out, all the other bulbs will continue to function. <u>We therefore conclude that the setup path of bulbs in the series circuit </u><u>is</u><u> independent and complete</u>

<u />

Hence, "In <u>parallel circuits</u>, each of the bulbs would be  set up in paths independent and complete."

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A student has 3.86 g of iron metal. How many moles of iron does the student have? Show your work.
GaryK [48]

Answer:

The answer to your question is:

a) 0.069 moles of Iron

b) 0.052 moles of Oxygen

Explanation:

Data

mass Iron = 3.86 g

moles = ?

Atomic weight Fe = 56 g

Process

a) Solve it using a rule of three

                                56 g of Fe ---------------- 1 mol

                               3.86 g ----------------------  x

                                x = (3.86 x 1) / 56

                                x = 0.069 moles of Iron

b)

Balanced Equation

                              4Fe  +  3O₂  ⇒   2Fe₂O₃

Solve it using a rule of three

                              4 moles of Fe -----------------  3 moles of O₂

                              0.069 moles of Fe ---------   x

                             x = (0.069 x 3) / 4

                             x = 0.052 moles of Oxygen

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