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Korvikt [17]
3 years ago
7

Calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution​

Chemistry
1 answer:
sineoko [7]3 years ago
8 0

Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject

Explanation:  so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³  so all we have to do is to find the molecular relative mass(mr) .

to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.

NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass

now we fix it in our formulae which is m=n× mr

m=1.5× 40 =60 so our mass is 60grams or 60g

HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment

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Which types of reactions would result in a change in temperature?
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Which kind of force is a dipole-dipole force?
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Answer:

Explanation:

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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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3 years ago
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