<img src="https://tex.z-dn.net/?f=%20-%2011%20%3D%207%20-%20x" id="TexFormula1" title=" - 11 = 7 - x" alt=" - 11 = 7

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slavikrds [6]

3 years ago

"absmiddle" class="latex-formula">
what is X

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

X = 18
if you need the steps i could give them to you just ask!
Hope that helped!
:)

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Find the measure of the missing angles.

salantis [7]

Applying the vertical angle theorem, the measure of the missing angles are:

e = 31

f = 72

d = 77

<h3>What is the Vertical Angle Theorem?</h3>

The vertical angles theorem states that two angles that are vertically opposite to each other have equal measures.

Angle e and 31 degrees are vertical angles. Therefore, based on the vertical angles theorem,

e = 31 degrees.

Also, d = 77 degrees [vertical angles theorem].

e + 77 + f = 180 degrees [straight line angles have a sum of 180 degrees].

Substitute the value of e into the equation

31 + 77 + f = 180

108 + f = 180

Subtract 108 from both sides

108 + f - 108 = 180 - 108

f = 72 degrees.

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1 year ago

Vinvika [58]

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On a coordinate plane, square p q r s is shown. point p is at (4, 2), point q is at (8, 5), point r is at (5, 9), and point s is

Masteriza [31]

A statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is: option D.

<h3>How to calculate the slope of a line?</h3>

Mathematically, the slope of a line is given by the following formula;

$Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}$

For line RP, we have:

$Slope = \frac{9\;-\;2}{5\;-\;4}\\\\Slope = \frac{7}{1}$

Slope RP = 7.

For line SQ, we have:

$Slope = \frac{6\;-\;5}{1\;-\;8}\\\\Slope = \frac{1}{-7}$

Slope SQ = negative one-sevenths.

For the midpoint, we have:

In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

Midpoint on x-coordinate = (8 + 1)/2 = 9/2 = 4.5.

Midpoint on y-coordinate = (9 + 2)/2 = 11/2 = 5.5.

In conclusion, a statement which proves that the diagonals of square PQRS are perpendicular bisectors of each other is that the midpoint of both diagonals is (4.5, 5.5), the slope of RP is 7, and the slope of SQ is negative one-sevenths.

Read more on squares here: brainly.com/question/2882032

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