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kotykmax [81]
3 years ago
7

Use the given transformation to evaluate the integral.

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

For the transformation

\begin{cases}x=7u+v\\y=u+7v\end{cases}

the Jacobian is

\dfrac{\partial(x,y)}{\partial(u,v)}=\begin{bmatrix}7&1\\1&7\end{bmatrix}

with determinant

\det\left(\begin{bmatrix}7&1\\1&7\end{bmatrix}\right)=48

The vertices of the triangle in the u,v-plane are

(x,y)=(0,0)\implies(u,v)=(0,0)

(x,y)=(7,1)\implies(u,v)=(1,0)

(x,y)=(1,7)\implies(u,v)=(0,1)

Then the integral is

\displaystyle\iint_R(x-8y)\,\mathrm dA=-48\int_0^1\int_0^{1-v}(u+55v)\,\mathrm du\,\mathrm dv=\boxed{-448}

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John invested his inheritance of $12000 in 3 different funds part in a money market fund paying 3% interest annually Parton monu
Leokris [45]

Answer:

John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

John invested his inheritance of $12,000 in three different funds: part in a money-market fund paying 3% interest annually; part in municipal bonds paying 4% annually; and the rest in mutual funds paying 7% annually. John invested $4,000 more in mutual funds than he invested in municipal bonds. The total interest earned in one year was $670. How much did he invest in each type of fund?

The explanation of the answer is now given as follows:

Let a, b and c represent the amount invested in money-market fund, municipal bonds and mutual funds respectively. Therefore, the sum of the three principal amounts can be represented as follows:

a + b + c = 12,000 ……………………….. (1)

Since John invested $4,000 more in mutual funds than he invested in municipal bonds, we have:

c = b + 4,000 ……………………………. (2)

The total amount of interest earned from each fund can be represented as follows:

0.03a + 0.04b + 0.07c = 670 ………………. (3)

Substituting equation (2) into equation (1), we have:

a + b + b + 4,000 = 12,000

a + 2b = 12,000 – 4,000

a + 2b = 8,000

a = 8,000 – 2b ……………………….. (4)

Also, substituting equation (2) into equation (3), we have:

0.03a + 0.04b + 0.07(b + 4,000) = 670

0.03a + 0.04b + 0.07b + 280 = 670

0.03a + 0.04b + 0.07b 0 = 670 – 280

0.03a + 0.11b = 390 ,,,,,,,,,,,,,,,,,,,,,, (5)

Substituting equation (4) into equation (5) and solve for b, we have:

0.03(8,000 – 2b) + 0.11b = 390

240 – 0.06b + 0.11b = 390

240 + 0.05b = 390

0.05b = 390 – 240

0.05b = 150

b = 150 / 0.05

b = 3,000

Substituting b = 3,000 into equation (2), we have:

c = 3,000 + 4,000

c = 7,000

Also, substituting b = 3,000 into equation (4), we have:

a = 8,000 – (2 * 3,000)

a = 8,000 – 6,000

a = 2,000

Therefore, John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

8 0
3 years ago
What are the solutions of x² + 6x - 6 = 10?
Likurg_2 [28]

Answer: x=- 8 or x=2


Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. The quadratic  equation is:

x^{2}+6x-6-10=0\\x^{2}+6x-16=0

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}

x_1=-8\\x_2=2


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