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mash [69]
3 years ago
6

What’s the answer to this

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0
I’m pretty sure the formula is 4/3 • pie • radius^3 (the 3 is to the third power)
You might be interested in
Find the indicated term of the given arithmetic sequence. a1=45, d= -3, n=10
klasskru [66]

In this sequence, we're given the first term, which is 45.

The difference between each term is -3, which means 3 will be subtracted in each term.

We're asked to find the value of the tenth term, and we can do so by using this formula:

a(n) = a(1) + d(n - 1)

Replace values.

a(10) = 45 + -3(9)

a(10) = 18

<h3>The value of the tenth term is 18.</h3>
3 0
3 years ago
Read 2 more answers
The mean per capita income is 16,127 dollars per annum with a variance of 682,276. What is the probability that the sample mean
MakcuM [25]

Answer:

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The standard deviation is the square root of the variance. So

\mu = 16127, \sigma = \sqrt{682276} = 826, n = 476, s = \frac{826}{\sqrt{476}} = 37.86

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Either it differs by 104 or less dollars, or it differs by more than 104 dollars. The sum of the probabilities of these events is 100. I am going to find the probability that it differs by 104 or less dollars first.

Probability that it differs by 104 or less dollars first.

pvalue of Z when X = 16127 + 104 = 16231 subtracted by the pvalue of Z when X = 16127 - 104 = 16023. So

X = 16231

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16231 - 16127}{37.86}

Z = 2.75

Z = 2.75 has a pvalue of 0.9970

X = 16023

Z = \frac{X - \mu}{s}

Z = \frac{16023 - 16127}{37.86}

Z = -2.75

Z = -2.75 has a pvalue of 0.0030

0.9970 - 0.0030 = 0.9940

99.40% probability that it differs by 104 or less.

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

p + 99.40 = 100

p = 0.60

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

7 0
3 years ago
In a sample of 1000 cases, the mean of a certain test is 14 and the standard deviation is 2.5. Assume the distribution to be nor
Maslowich

Answer:

The top 20% of the students will score at least 2.1 points above the mean.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The mean of a certain test is 14 and the standard deviation is 2.5.

This means that \mu = 14, \sigma = 2.5

The top 20% of the students will score how many points above the mean

Their score is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84.

Their score is:

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 14}{2.5}

X - 14 = 0.84*2.5

X = 16.1

16.1 - 14 = 2.1

The top 20% of the students will score at least 2.1 points above the mean.

7 0
2 years ago
Will mark brainliest !!!
Wittaler [7]

Answer:

just mark points it is very easy

5 0
3 years ago
The measurement around the trunk of a tree just below shoulder height is called girth. The largest known american beech tree in
Bumek [7]

Answer:

24 1/6 - 19 5/12=

24 1/6÷12- 19 5/12÷12

24 2/2- 19 5/1= 5 3/1

3÷1= 3

5÷3= 3 1/2

Step-by-step explanation:

Step 1: Do the lcd and the number in between what you do is multiply the number next to it.

Step 2: Then subtract the mixed numbers and you get your answer.

Step 3: Divide 3 by 1

Step 4: Divide 3 by 5 and answer is 3 1/2

3 0
3 years ago
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