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taurus [48]
3 years ago
10

A deep-sea exploring ship is pulling up a diver at the rate of 25 ft./min. the driver is 200 feet below sea level how deep it wa

s the diver 10 minutes ago show your thinking
Mathematics
2 answers:
Rainbow [258]3 years ago
7 0

Answer:

Ten minutes ago, the diver was  450  feet below sea level.

Step-by-step explanation:

Since the diver is being pulled up, measuring his movement for the past  10 minutes requires that we use  −25  for the movement over those  10  minutes. So, his depth  10 minutes ago is given by the expression

−200−25(10)

−200

−250

−450

So,  10  minutes ago, the diver was  450 feet below sea level.

lara [203]3 years ago
3 0

Answer:

The diver 450 feet deep into sea 10 minutes ago.

Step-by-step explanation:

At present position ,depth at which diver was = 200 feet

Rate at which diver is pulled up = 25 ft/min

Let the depth of the diver 10 minutes ago be x

The depth of the diver 10 minutes ago will be sum of present position and distance covered by exploring ship by pulling diver in a 10 minutes.

x = 200 + 25ft/min × 10 = 200 ft + 250 ft = 450 ft

The diver 450 feet deep into sea 10 minutes ago.

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Answer with Step-by-step explanation:

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Hence, for all elements of Zx^2-5x-1is odd.

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