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krok68 [10]
4 years ago
14

What is moment? What are the two factors which affect moment​

Physics
1 answer:
IgorC [24]4 years ago
7 0

Explanation:

moment is an expression involving the product of a distance and physical quantities.

-the size of force applied.

-the perpendicular distance from the pivot to the line of action of the force

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What is the work done in lifting 60 kg of blocks to a height of 20m
erastovalidia [21]

Answer:

The answer is 1200

Explanation:

5 0
2 years ago
PLEASE PLEASE HELP!
vichka [17]
Well, the relationship between the net force and mass and acceleration of an object are directly related, as per the equation - Fnet = ma.

Thus the solution is A. As the net force of an object decreases, the object's acceleration also decreases, mass is kept constant.
5 0
4 years ago
What is the first step in cell division?
ohaa [14]

Answer:

d

Explanation:

4 0
3 years ago
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
A 50.0-kg skater begins a spin with an angular speed of 4.0 rad/s. By changing the position of her arms, the skater decreases he
Pani-rosa [81]

Answer:

The Skater's final angular speed =8rad/s

Explanation:

Let initial momentum of inertia be I1

Let final momentum of inertia be I2

But I2= I1/2

It is decreased by one-half

There is no external torque on the system, therefore

I1w1=I2w2

I1×4=(I1/2)×w2

Dividing through by I1 on both sides leaves you with:

4=w2/2

Cross multiply

W2=4×2=8rad/s

4 0
4 years ago
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