What happens to the electrical energy that does not become light energy?

An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is atte

Lorico [155]

initial velocity=15m/s=u
Acceleration=a=5m/s^2
Final velocity=v=30m/s
Distance be s

Using 3rd equation of kinematics

$\\ \rm\longmapsto v^2-u^2=2as$

$\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}$

$\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}$

$\\ \rm\longmapsto s=\dfrac{900-225}{10}$

$\\ \rm\longmapsto s=\dfrac{675}{10}$

$\\ \rm\longmapsto s=67.5m$

5 0

3 years ago

Whic two types of cells are required during the process of osteogenesis

Mkey [24]

Answer:

Bone homeostasis involves multiple but coordinated cellular and molecular events. Two main types of cells are responsible for bone metabolism: osteoblasts (which secrete new bone), and osteoclasts (which break bone down).

Explanation:

3 0

3 years ago

A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is

mihalych1998 [28]

Answer:

a) $v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

b) $\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

c) $t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

d) $Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that $v_y = 2 m/s$ represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is $V_x= 4.8 m/s$

And we want to find the velocity of the motord board relative to the Earth $v_m$

And we can find this velocity from the Pythagorean Theorem.

$v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

Part b

We can find the direction with the following formula:

$\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

$D = Vt$

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

$t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

Part d

For this case we can use the same definition but now using the y compnent we have:

$Y = v_y t$

And replacing we got:

$Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

7 0

3 years ago

The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column

JulsSmile [24]

Answer:

1) f = 214 Hz , 2) answer is c , 3) f = 428 Hz , 4) f₂ = 428 Hz , f₃ = 643Hz

Explanation:

1) A tube with both ends open, the standing wave has a maximum amplitude and a node in its center, therefore

L = λ / 2

λ = 2L

λ = 2 0.8

λ = 1.6 m

wavelength and frequency are related to the speed of sound (v = 343 m / s)

v =λ f

f = v / λ

f = 343 / 1.6

f = 214 Hz

2) In this case the air comes out through the open hole, so we can assume that the length of the tube is reduced

λ' = 2 L ’

as L ’<L₀

λ' <λ₀

f = v / λ'

f' > fo

the correct answer is c

3) in this case the length is L = 0.40 m

λ = 2 0.4 = 0.8 m

f = 343 / 0.8

f = 428 Hz

4) the different harmonics are described by the expression

λ = 2L / n n = 1, 2, 3

λ₂ = L

f₂ = 343 / 0.8

f₂ = 428 Hz

λ₃ = 2 0.8 / 3

λ₃ = 0.533 m

f₃ = 343 / 0.533

f₃ = 643 Hz

4,1) as we have two maximums at the ends, all integer multiples are present

the answer is C

E) the length of an open pipe created that has a wavelength of lam = 1.6 m is requested

in this pipe there is a maximum in the open part and a node in the closed part, so the expression

L = λ / 4

L = 1.6 / 4

L = 0.4 m

the answer is C

F) in this type of pipe the general expression is

λ = 4L / n n = 1, 3, 5 (2n + 1)

therefore only odd values can produce standing waves

λ₃ = 4L / 3

λ₃ = 4 0.4 / 3

λ₃ = 0.533

f₃ = 343 / 0.533

f₃ = 643 Hz

5 0

3 years ago

Which of these describe the composition of earths atmosphere?

Alja [10]

Earth's atmosphere is a <em>mixture</em> of gases that have
not reacted to become chemical compounds.

6 0

3 years ago