They gather data about the natural world.
hope that helped! :)
my bad I was in a herie last time can you please answer my question , I am going to give you the 5 points back for this question and extra 30 points ,
Explanation:
first its going to say 10 points for my question but after that I well make answer a small question and give you 30points. like whats your favorite color . stay tuned .
Answer:
The force per unit length (N/m) on the top wire is 16.842 N/m
Explanation:
Given;
distance between the two parallel wire, d = 38 cm = 0.38 m
current in the first wire, I₁ = 4.0 kA
current in the second wire, I₂ = 8.0 kA
Force per unit length, between two parallel wires is given as;
where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
Substitute the given values in the above equation and calculate the force per unit length
Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m
Answer: Angle 59 degree
Explanation: Given that the
n1 = 1.0
n2 = 1.5
Øi = 35 degree
From Snell law, which says that
n1/n2 = sinØ1/ sinØ2
Substitute all the parameters into the formula
1/1.5 = sin 35/sinØ2
Cross multiply
Sin Ø2 = 1.5 sin35
SinØ2 = 1.5 × 0.573 = 0.860
Ø2 = sin^-1(0.860)
Ø2 = 59.36 degree
Ø2 = 59 degree ( approximately)
It has angle 59 degree when passing from air to glass
Answer: 16.3 seconds
Explanation: Given that the
Initial velocity U = 80 ft/s
Let's first calculate the maximum height reached by using third equation of motion.
V^2 = U^2 - 2gH
Where V = final velocity and H = maximum height.
Since the toy is moving against the gravity, g will be negative.
At maximum height, V = 0
0 = 80^2 - 2 × 9.81 × H
6400 = 19.62H
H = 6400/19.62
H = 326.2
Let's us second equation of motion to find time.
H = Ut - 1/2gt^2
Let assume that the ball is dropped from the maximum height. Then,
U = 0. The equation will be reduced to
H = 1/2gt^2
326.2 = 1/2 × 9.81 × t^2
326.2 = 4.905t^2
t^2 = 326.2/4.905
t = sqrt( 66.5 )
t = 8.15 seconds
The time it will take for the rocket to return to ground level will be 2t.
That is, 2 × 8.15 = 16.3 seconds
