Explanation:
Work is the product of force and distance.
W = F×d
W = (22 N) × (16 m)
W = 352 J
Answer:
3.1 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
40 N = (13 kg) a
a ≈ 3.1 m/s²
I think it might be Jupiter—
Answer:
vT = v0/3
Explanation:
The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R
Since F = F0 = F'
GMm/R² = m(v0)²/R
GM = (v0)²R (1)
Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R
Since F1 = F'
GMm/27R² = m(vT)²/3R
GM = 27(vT)²R/3
GM = 9(vT)²R (2)
Equating (1) and (2),
(v0)²R = 9(vT)²R
dividing through by R, we have
9(vT)² = (v0)²
dividing through by 9, we have
(vT)² = (v0)²/9
taking square-root of both sides,
vT = v0/3
You said 2 revolutions every 0.08 seconds
1 revolution = 2pi radians.
A). The 'unit rate' is (2 rev) x (2pi / 0.08 sec) = 50pi radians/sec. =
157.1 radians per sec (rounded)
B). Radius of the wheel = 30 cm
Circumference = 2pi R = 60pi cm = 188.5 cm (rounded)
Rotation speed = 2 revs per 0.08 sec
Linear speed = 2 x 60pi cm per 0.08 sec
(120pi cm) / (0.08 sec) = 47.12 meters per sec
C). Frequency = (revs) per second
= (2) / (0.08 sec) = 25 per second .
