Answer:
Check the attached document for the solutions, cheers
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8
p2 - 2p + 8p - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (p-2)
Add up the last 2 terms, pulling out common factors :
8 • (p-2)
Step-5 : Add up the four terms of step 4 :
(p+8) • (p-2)
Which is the desired factorization
Answer:
3bat + 3b² - 6a²t²
Step-by-step explanation:
First you have to expand it to get;
3b(b - at) + 6at(b - at)
Then you can now multiply.
3b² - 3bat + 6bat - 6at²
Group like terms
6bat - 3bat + 3b² -6at²
3bat + 3b² - 6a²t²
Answer:
5
5
1/3
Step-by-step explanation:
Step-by-step explanation:
Day 1: 1200g / 2¹ = 600g
Day 2: 1200g / 2² = 300g
Day 3: 1200g / 2³ = 150g
The pattern is the amount of radioactive substance on day n is 1200 / (2^n).
Therefore, we have to find n where 2^n > 1200.
The first such n is 11 (2¹¹ = 2048).
Hence, there will be less than 1 gram on day 11.