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3 years ago

Meriwether Lewis and William Clark were

History

2 answers:

Law Incorporation [45]3 years ago

7 0

Answer:

Correct answer is: explorers sent by Jefferson to find a water route to the Pacific.

Explanation:

Pie3 years ago

4 0

Answer:

Correct answer is explorers sent by Jefferson to find a water route to the Pacific.

Explanation:

First option is correct as two close friends Meriwether Lewis and William Clark were sent to explore the newly acquired Western territories and if possible to find a route to the Pacific Ocean.

Second option is not correct as those were Monroe and Livingston (Louisiana Purchase).

Third option is not correct because in that battle United States army was led by Wayne and Wilkinson.

Fourth option is not correct although both of them were governors of certain territories. Lewis was a 2nd Governor of Louisiana territory, while Clark was 4th Governor of Missouri Territory.

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(x+1/x-1 - x-1/x+1 - 4x/x^2 +1) + 4x/x^4-1

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Answer:

$\frac{12x}{x^4-1}$

Explanation:

Given

$(\frac{x+1}{x-1} - \frac{x-1}{x+1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Required

Solve:

Take L.C.M of the first two fractions

$(\frac{(x+1)(x+1)-(x-1)(x-1)}{(x-1)(x+1)} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{(x+1)(x+1)-(x-1)(x-1)}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{x^2+2x+1-(x^2-2x+1)}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{x^2+2x+1-x^2+2x-1}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Collect Like Terms

$(\frac{x^2-x^2+2x+2x+1-1}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

$(\frac{4x}{x^2-1} - \frac{4x}{x^2 + 1}) + \frac{4x}{x^4 - 1}$

Solve the expression in bracket

$(\frac{4x(x^2+1) - 4x(x^2-1)}{(x^2-1)(x^2+1)} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x(x^2+1) - 4x(x^2-1)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x^3+4x - 4x^3+4x)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$(\frac{4x^3- 4x^3+4x +4x)}{x^4-1} ) + \frac{4x}{x^4 - 1}$

$\frac{8x}{x^4-1} + \frac{4x}{x^4 - 1}$

Take LCM

$\frac{8x+4x}{x^4-1}$

$\frac{12x}{x^4-1}$

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