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saul85 [17]
3 years ago
8

Whats is a unit rate

Mathematics
2 answers:
Blizzard [7]3 years ago
6 0
Unit rate is used to compare quantities in which the second quantity is one. Common examples of unit rate would include, miles per hour earnings per hour cost per gallon.
maria [59]3 years ago
4 0

Answer:

A unit rate is a comparison of a number to one indifferent unit. It is written as a fraction.

YOU Divide to simplify and always include units

Step-by-step explanation:

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Tahmid has 96 G.I. Joe action figures and Sandeep has one-third as much as Tahmid does. How many figures must Tahmid give Sandee
Ann [662]
Tahmid has 96 figures, Sandeep has 1/3 of it so 
96(1/3) = 96/3 = 32
Sandeep has 32 figures

Tahmid 96 ; Sandeep 32

How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give. 
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each. 
6 0
3 years ago
Of the students at Milton middle school 171 are girls if 45% of the students are girls how many total students are there at milt
Volgvan

Answer:

380

Step-by-step explanation:

171:45=3,8

3,8*100=380

8 0
3 years ago
Please help please help please help please help please help first to asnwer gets brainleyist
Licemer1 [7]
The answer is B. 60 because length Time width 5x12
6 0
3 years ago
89.891 to the nearest ten thousands place
Orlov [11]
89.890 Is what I would think it would be. Hope it helped.

7 0
3 years ago
"assume that s is a non-empty set of real numbers which is bounded above and lambda is the least upper bound. Prove that for all
s2008m [1.1K]

By definition, if \lambda is the least upper bound of the set S, it means two thing:

  • \forall x \in S,\ x \leq \lambda
  • \forall \varepsilon>0,\ \exists x \in S:\ x>\lambda-\varepsilon

In other words, the least upper bound of a set is greater than or equal to every single element of the set, but it is "close enough" to the elements of the set, because you guaranteed to find elements in the set between \lambda-\varepsilon and \lambda

For example, pick S = [1,10). Obvisouly, the least upper bound is \lambda = 10. In fact, every number in [1,10) is smaller than 10, but as soon as you take away something from 10, say 0.01, you get 9.99, and there are elements in S greater than 9.99, say 9.9999.

So, the claim is basically proven by definition: if \beta < \lambda, let 0 < \delta = \lambda - \beta. By definition, there exists \alpha \in S:\ \alpha > \lambda - \delta.

8 0
3 years ago
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