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BARSIC [14]
3 years ago
14

Help me please I don’t get it

Mathematics
2 answers:
gladu [14]3 years ago
8 0
Hey there! so the point is to try and figure out how many combinations of 2 letters exist. one way to accomplish this is to make a list. I would start with h. So your list for h would be (h,h) (h,o) (h,p) (h,e) then move on to your next letter. hope this helps!
svet-max [94.6K]3 years ago
4 0
The answer to B is: HP, HE, H and O, HH, OO, EE, PP, PE, PO, and EO

the answer to a would be 10
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Acil arkadaslar !!!!!!!!!!!!!!!!!!!!
kotegsom [21]

Answer:

please try asking in english

Step-by-step explanation:

try at least

5 0
3 years ago
Directions - solve the liner system. enter your answer as an ordered pair. 2x + 3y = 31 y = x + 7
Leya [2.2K]

(1) 2x + 3y = 31 y

(2) 2x + 3y = x + 7

(3) 31y = x + 7

(3) x = 31y - 7

(2) 2(31y - 7) + 3y = 31y - 7 + 7 ; 62y - 14 + 3y = 31y ; 34y = 14 ; y = 14/34 ; y = 7/17

(3) x = 31y - 7 ; x = 31*(7/17) - 7 ; x = (217 - 119)/17 = 98/17

x = 98/17 ≈ 5.76

y = 7/17 ≈ 0.41

8 0
3 years ago
8. To calculate 159 - 73, a student writes the follow-
Evgen [1.6K]

The question is an illustration of solving equations using estimates.

The student's strategy makes sense because he uses estimation to solve the given equation

The correct sequence of equation is as follows:

  • \mathbf{159 - 73}
  • \mathbf{159 - 73 =160 - 70- 1 - 3}
  • \mathbf{159 - 73 =90- 4}
  • \mathbf{159 - 73 =86}

We have:

\mathbf{159 - 73}

Add 0 to the equation

\mathbf{159 - 73 =159 + 0- 73}

Express 0 as 1 - 1

\mathbf{159 - 73 =159 + 1 - 1- 73}

\mathbf{159 - 73 =160 - 1- 73}

Add another 0

\mathbf{159 - 73 =160 - 1- 73 + 0}

Express 0 as 3 - 3

\mathbf{159 - 73 =160 - 1- 73 + 3 - 3}

\mathbf{159 - 73 =160 - 1- 70 - 3}

Rewrite as:

\mathbf{159 - 73 =160 - 70- 1 - 3}

Solve

\mathbf{159 - 73 =90- 4}

\mathbf{159 - 73 =86}

Read more about estimation and equations at:

brainly.com/question/18454732

7 0
3 years ago
Please help me ASAP! Worth 11 points
saul85 [17]

Answer:

x axis, then translate x+6, y+1

5 0
3 years ago
Read 2 more answers
PQ has endpoints at PH(7, -11) and Q(-5,-8). Find the slope of PQ
shusha [124]
Slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so
slope beteen (7,-11) and (-5,-8) is

(-8-(-11))/(-5-7)=(-8+11)/(-12)=3/-12=-1/4

slope=-1/4
4 0
3 years ago
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