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Phantasy [73]
4 years ago
9

If gas in a cylinder is maintained at a constant temperature​ T, the pressure P is related to the volume V by a formula of the f

orm P = \frac{nRT}{V - nb} - \frac{an^2}{V^2}.
Physics
1 answer:
Mkey [24]4 years ago
6 0

The given question is incomplete. The complete question is as follows.

If gas in a cylinder is maintained at a constant temperature T, the pressure P is related to the volume V by a formula of the form

P = \frac{nRT}{(V - nb)} - \frac{an^2}{V^2}, in which a, b, n, and R are constants. Find \frac{dP}{dV}.

Explanation:

We will use the quotient rule for each of the two terms on the right side as follows.

        P = \frac{nRT}{V - nb} - \frac{an^{2}}{V^{2}}

\frac{dP}{dV} = \frac{0(V - nb) - nRT(1)}{(V - nb)^{2}} - \frac{0(V)^{2} - an^{2}(2V)}{V^{4}}

            = \frac{-nRT}{(V - nb)^{2}} - \frac{-2an^{2}V}{V^{4}}

            = \frac{-nRT}{(V - nb)^{2}} + \frac{2an^{2}}{V^{3}}

            = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}

   \frac{dP}{dV} = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}

Thus, we can conclude that the value of \frac{dP}{dV} = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}.

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Explanation:

Let C_1 and C_2 denote the capacitance of these two capacitors.

When these two capacitors are connected in parallel, the combined capacitance will be the sum of C_1 and C_2. (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)

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On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:

\displaystyle \frac{1}{C(\text{series})} = \frac{1}{C_1} + \frac{1}{C_2}.

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The question states that:

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Let the capacitance of these two capacitors be x\; \rm \mu F and y\; \rm \mu F. The two equations will become:

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Hence, the y in the second equation here can be replaced with (35 - x). That equation would then become:

\displaystyle \frac{1}{x} + \frac{1}{35 - x} = \frac{1}{4.8}.

Solve for x:

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x^2 - 35 \, x + 168 = 0.

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Substitute back into the equation y = 35 - x for y:

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