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chubhunter [2.5K]
3 years ago
6

Which factor affects the force of gravity between objects? Check all that apply. A.direction

Physics
2 answers:
eduard3 years ago
5 0

Answer:b c

Explanation:

Leviafan [203]3 years ago
3 0

The gravitational force between two masses is given by the formula

F=G\dfrac{Mm}{r^2}

where G is the <em>gravitational constant, </em>M is the larger mass, m is the smaller mass, and r is the distance between the centers of the objects. The values we can change here to affect that gravitational force are the <em>mass </em>and the <em>distance</em>. Time and shape have no impact on this force.

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An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then
gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

a=\frac{dv}{dt}=1.76

So, the velocity can be obtained by integrating this expression:

v=1.76t

The velocity is, by definition: v=\frac{dx}{dt}, so

dx=1.76tdt\\x=1.76\frac{t^{2}}{2}.

Do x=11 in order to find the time spent.

11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s

At this time the velocity is: v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}

This velocity remains constant in the section 2, so for that section the movement equation is:

x=v*t\\t=\frac{x}{v}

The left distance is 89 meters, and the velocity is 6.2225\frac{m}{s}, so:

t=\frac{89}{6.2225}=14.303s

So, the total time is 14.303+3.5355s=17.838s

7 0
3 years ago
A 36,287 kg truck has a momentum of 907,175 kg • . What is the truck’s velocity?
Snowcat [4.5K]
By definition,
Momentum = Mass * Velocity

Let v =  the velocity of the truck, m/s
The mass of the truck is 36,287 kg.
The momentum is 907,175 (kg-m)/s.

Therefore
907,175 (kg-m)/s = (36287 kg)*(v m/s)
v = 907175/36287 = 25 m/s

Answer: 25 m/s

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What patterns are caused by the Earth, Sun, and Moon systems?
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3 years ago
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You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving
BabaBlast [244]

Y₀ = initial position of the balloon at the top of the building = 44 m

Y = final position of the balloon at halfway down the building = 44/2 = 22 m

a = acceleration of the balloon = - 9.8 m/s²

v₀ = initial velocity of the balloon = 0 m/s

v = final velocity of the balloon = ?

using the kinematics equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 0² + 2 (- 9.8) (22 - 44)

v = 20.78 m/s

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3 years ago
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