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2 years ago

Please help me it takes do long to do this please

Mathematics

2 answers:

vladimir1956 [14]2 years ago

3 0

Answer:

I really don't know , I am in 7th grade

Dmitriy789 [7]2 years ago

3 0

Answer:

x = 121°

Step-by-step explanation:

The lower left vertex and 115 are adjacent and supplementary, thus

left vertex = 180° - 115° = 65°

The angle round a point = 360°, so the top vertex is

360° - 304° = 56°

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

x is an exterior angle of the triangle, thus

x = 65° + 56° = 121°

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Using the order of operations, what should be done first to evaluate mc019-1.jpg?

stellarik [79]

Answer:

"Multiply –6 and 3"

Step-by-step explanation:

For order of operations, we follow the rule PEMDAS

We do PARENTHESIS first, then
Exponents, then
Multiplication, then
Division, then
Addition, then
Subtraction

In this problem, we have parenthesis, so (-6)(3) should be done first.

Hence, we should multiply -6 and 3.

8 0

3 years ago

Read 2 more answers

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago

Anson collected 720 seashells. Then he gave 209 seashells to

vaieri [72.5K]

Answer:

18.75%

Step-by-step explanation:

720 - (209+376) =

720 - 585 = 135

135/720 = 0.1875 --> 18.75%

3 0

2 years ago

Six times a number is greater than 20 more than that number. What are the possible values of that number? On-4 On>4 20 On>

Vaselesa [24]

Answer:

a > 4

Step-by-step explanation:

$6a > 20 + a \\ collect \: like \: terms \\ 6a - a > 20 \\ then \: add \\ 5a \: > 20 \\ divide \: both \: sides \: by \: 5 \\ \frac{5a}{5} > \frac{20}{5} \\ a > 4$

8 0

2 years ago

25 POINTS HOW MUCH I NEED HELP PLEASE IM BEGGINGGG

Ghella [55]

Answer:

Step-by-step explanation:

It's a vertical line. Regardless of what point you go to on the line, it always has a value of -3 because it is going vertically (up and down) at -3.

Therefore the equation of a line is x = -3

8 0

3 years ago