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3 years ago

15

What is the factorization of the polynomial below? x^3 + 8x^2 + 17x + 10

2 answers:

faltersainse [42]3 years ago

8 0

Answer:

This is your answer.

Step-by-step explanation:

Hope is helps!!

DaniilM [7]3 years ago

8 0

Answer: (x+1) (x+2) (x+5)

Step-by-step explanation:

You might be interested in

Solve the formula C= 3.14*d ?

gavmur [86]

Answer: $d=\frac{50C}{157}$

Step-by-step explanation:

$C=3.14d$

$3.14d=C$

$3.14d\cdot \:100=C\cdot \:100$

$314d=C\cdot \:100$

$\frac{314d}{314}=\frac{C\cdot \:100}{314}$

$d=\frac{50C}{157}$

7 0

3 years ago

During the 2008-2009 school year, the average ratio of teachers to students in the public elementary and secondary schools was a

Vlad1618 [11]

Answer:

I believe the answer is 56

Step-by-step explanation:

848÷15

6 0

4 years ago

A checking account rounds the amount of money deposited to the nearest hundredths place. After tax returns on April 15th, Yuan e

ludmilkaskok [199]

Answer:

$\boxed{\text{\$336.35}}$

Step-by-step explanation:

Yuan earned $336.3457.

You are asked to round this number to the nearest hundredth, that is, so there are only two digits after the decimal.

$336.34|57

A rule in rounding numbers is: if the first figure to be dropped is 5 with any nonzero digits following it, then the last figure kept should be rounded up (increased by 1).

The number becomes $336.35.

$\boxed{\large \textbf{\$336.35}} \text{ was placed in Yuan's checking account}$

6 0

4 years ago

120 divided by what equals 1.2

Nikitich [7]

100 is the correct answer

6 0

3 years ago

The scores of fourth grade students on a mathematics achievement test follow a normal distribution with a mean of 75 and standar

mamaluj [8]

Answer:

The appropriate solution is:

(a) 0.1056

(b) 0

(c) 0.9544

Step-by-step explanation:

The given values are:

Mean,

$\mu = 75$

Standard deviation,

$\sigma = 4$

(a)

⇒ $P(x>80)=1-(x$

$=1-P[\frac{x-\mu}{\sigma}$

$=1-P[\frac{x-\mu}{\sigma}$

$=1-P(z$

By using the table, we get

$=1-0.8944$

$=0.1056$

(b)

According to the question, the values are:

$n$ = 64

$\mu_\bar{x}$ = 75

Now,

⇒ $\sigma_\bar{x}$ = $\frac{\sigma}{\sqrt{n} }$

= $\frac{4}{\sqrt{64} }$

= $\frac{4}{8}$

= $0.5$

⇒ $P(\bar {x} >80 ) = 1 - P(\bar x$

$=1 - P[\frac{(\bar x-\mu_\bar x)}{\sigma \bar x} < \frac{80-75}{0.5} ]$

$=1-P(z$

By using the table, we get

$=1-1$

$=0$

(c)

As we know,

⇒ $\sigma_\bar x$ = $\frac{\sigma}{\sqrt{n} }$

= $\frac{4}{\sqrt{64} }$

= $\frac{4}{8}$

= $0.5$

then,

= $P(74< \bar x$

= $P[\frac{74-75}{0.5} < \frac{\bar x-\mu \bar x}{\sigma \bar x} < \frac{76-75}{0.5} ]$

= $P(-2$

= $P(z$

By using the table, we get

= $0.9772-0.0228$

= $0.9544$

7 0

3 years ago