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weqwewe [10]
3 years ago
14

What is the value of b in the triangle shown below?

Mathematics
2 answers:
Akimi4 [234]3 years ago
7 0

Answer:

b= 4 in.

Step-by-step explanation:

Ok. So the area of a triangle is base * height divided by 2.

So, the base is b and the height is 3b.

b*3b= 3b^2.

Now, divide that by 2.

(3b^2)/2.

Now, we know what the area is already- 24 in.^2. So, let's set the area expression that I found earlier equal to this area, since they're the same.

(3b^2)/2 = 24

3b^2 = 48

b^2 = 16

Ok. Let's stop here. Now, we square root both sides to obtain b, but we are presented with a problem here. B can equal both 4 and -4 right? Since -4*-4=16 and 4*4=16. However, it is impossible for a 2d shape to have negative measurements. So, the answer is 4.

12345 [234]3 years ago
4 0

Answer:

+4 in

Step-by-step explanation:

A= 1/2 x b x h

24=1/2 x b x 3b

b2=16

b=+4 or -4(N/A)

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4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
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Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
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