Question

Check picture for question and answer choices

Answer 1

Answer:

Therefore,

$x=b$ is the required value.

Step-by-step explanation:

If a ≠ 0, a ≠ 1 and

$\dfrac{ax-b}{a-1} =b$

To Find:

x = ?

Solution:

$\dfrac{ax-b}{a-1} =b\\\\ax-b=b(a-1)$

Applying Distributive Property i.e A(B+C)=AB+AC we get

$ax-b=b\times a-b\times 1\\\\ax-b=b\times a-b\\\\ax=b\times a-b+b\\\\ax=b\times a\\\\x=\dfrac{ba}{a}\\a\neq 0\ a\neq 1\\a\ will\ cancel\\\\ x=b$

Therefore,

$x=b$ is the required value.