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schepotkina [342]
3 years ago
11

What is the equation in point-slope form of the line passing through (1, 9) and (1, 11)? (5 points)​

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Marta_Voda [28]3 years ago
4 0

Answer:

y-9=0(x-1)

Step-by-step explanation:

first, find the slope with m=y2-y1/x2-x1

11-9=2

1-1=0

2/0 is undefined so i think you have to use 0

sorry if im wrong

i find it difficult when there is no slope

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How does the value of log 2 100 compare with the value of log 6 20?
lys-0071 [83]

Answer:

C

Step-by-step explanation:

Cuz I said so

4 0
2 years ago
Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti
Vikki [24]

Answer:

General Solution is y=x^{3}+cx^{2} and the particular solution is  y=x^{3}-\frac{1}{2}x^{2}

Step-by-step explanation:

x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}

This is a linear diffrential equation of type

\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)..................(i)

here p(x)=\frac{-2}{x}

q(x)=x^{2}

The solution of equation i is given by

y\times e^{\int p(x)dx}=\int  e^{\int p(x)dx}\times q(x)dx

we have e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}

Thus the solution becomes

\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+cy=x^{3}+cx^{2

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have 6=8+4c

Thus solving for c we get c = -1/2

Thus particular solution becomes

y=x^{3}-\frac{1}{2}x^{2}

5 0
3 years ago
Please help me out asappppppppp
Luba_88 [7]

Answer:

46

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the equation. (Find only the real solutions. Enter your answers as a comma-separated list.) x4 − 8x2 + 7 = 0
ryzh [129]

Answer: x=0 or x= plus or minus 2

Step-by-step explanation:

g(x)=x^4-8x^2+7

Critical numbers are the numbers where the first derivative is zero

g'(x)=4x^3-16x+0

=4x^3-16x

g'(x)=0

Implies

4x^3-16x=0

4x(x^2-4)=0

4x=0 OR x^2-4=0

x=0 or x^2=4

x=0 or x= plus or minus 2

5 0
3 years ago
Find the dimensions of the rectangle with area 289 square inches that has minimum perimeter, and then find the minimum perimeter
nalin [4]
 <span>To minimize the perimeter you should always have a square. 
sqrt(289) = 17 
The dimensions should be 17 X 17 

To see , try starting at length 1, and gradually increase the length. 
The height decreases at a faster rate than the length increases, up until you reach a square. 

Or if you want to use algebra, Say the width is 17-x 
Then the length is 289/(17-x) 

Now, this is bigger than 17+x, as shown here: 
289/(17-x) > 17+x 
289 > 289 - x^2 
which is true. 
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17 

Again, the dimensions should be a square. 17 X 17.</span>
4 0
3 years ago
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