All categories

2 years ago

3^9 times 3^7 in exponential form

Mathematics

2 answers:

Orlov [11]2 years ago

4 0

Answer:

You can just add the exponents power

9+7=16

So its 3^16 in exponential form

You can think of it like this.

for 3^9 its

3*3*3*3*3*3*3*3*3

And for 3^7 its

3*3*3*3*3*3*3

Now your multiplying them all together.

Really your jsut adding the value so in the end

3*3*3*3*3*3*3*3*3*3*3*3*3*3*3*3

So its

3^16

gladu [14]2 years ago

3 0

Answer:

3¹⁶

Step-by-step explanation:

While adding numbers with exponents, if the base of the numbers is same, then it will also be the same in the final answer and the exponents add

Hope this helps!

You might be interested in

HELP PLS ASAP WILL MARK BRAINLEIST IF YOU SHOW WORK

Vaselesa [24]

7) A. 1.8

divide 9 by 5

8) B. 0.444...

divide 4 by 9

9) You're correct: It's D. 3/5

Divide 1 1/5 by 2

3 0

3 years ago

IF YOU ARENT ANY OF THES PEOPLE PLZ DON'T ANSWER THIS QUESTION. Hobie, kkmmll44, Katyazamo.

Marianna [84]

The Associative Property say that it doesn't matter how we group the numbers (i.e. which we calculate first) when we add

(a + b) + c = a + (b + c)

The Commutative Property say we can swap numbers over and still get the same answer when we add

a + b = b + a

The Distributive Property:

a(b + c) = ab + ac

------------------------------------------

-3a + 4b + 5a + (-7b) = -3a + 5a + 4b + (-7b)

<h3>Answer: the commutative property</h3>

8 0

3 years ago

What is the equation of the line through (-6, -5) and (-4, -4)?

Norma-Jean [14]

Answer:

y = 1/2x -2

Step-by-step explanation:

The 2-point form of the equation for a line is useful for answering questions like this.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1 . . equation of a line through (x1, y1) and (x2, y2)

Filling in the given points, the equation becomes ...

y = (-4 -(-5))/(-4 -(-6))/(x -(-6)) -5

y = 1/2(x +6) -5

y = 1/2x -2

3 0

3 years ago

Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago

What is the answer to 3.4m+2.4m

polet [3.4K]

Answer:

5.8m

Step-by-step explanation:

8 0

3 years ago