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3 years ago

What is the prime factorization of 88?

2 answers:

8 0

Hello!

The prime factorization of 88 is 2³*11. 88 is made of 11 and 8. 8 is equivalent to 2³ so when 11 is multiplied by 2³, it equals 88.

So the prime factorization of 88 is 2³*11

I hope this helps!

Harlamova29_29 [7]3 years ago

7 0

Find the factors of 88

88/11 = 8
8/2 = 4
4/2 = 2

11 x 2 x 2 is the prime factorization of 88

hope this helps

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Porque es importante el uso de los angulos para un ingeniero civil

Tcecarenko [31]

Answer:

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4 years ago

Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)

timofeeve [1]

Answer: $x-2y-2=0$

Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

$x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75$

So, we have points $\left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )$

Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$

Let $\left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )$

So, equation is as follows :

$y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0$

4 0

4 years ago

Someone please help and make sure it’s right I have an f right now :(

blsea [12.9K]

Answer:b is the choice

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me please I will mark as brainliest!!

konstantin123 [22]

Answer:

A is answer

Step-by-step explanation:

Cuz once you solve it isn't a fraction any more

I think

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3 years ago

WILL RATE BRAINLIEST PLZ HELP<br> MUST EXPLAIN THO

madreJ [45]

Answer:

A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
D -- base 3, height 5

Step-by-step explanation:

A sort of straightforward way to approach this is to define base and height variables for each of the figures: ba, ha, bb, hb, bc, hc, bd, hd. Then the statements can be used to make equations in these variables.

0. hc = bc . . . . figure C is a square

1. ba = bd

2. ba = bb -1

3. hc = ba

4. hb = ha = bb

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Using equations 0 and 5, we find ...

hc² = 9 ⇒ hc = 3

From equation 3, ...

ba = 3

From equation 2, ...

3 = bb -1 ⇒ bb = 4

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bd = 3

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ha = hb = 4

Filling in the values we know in equation 6, we get ...

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A -- base 3, height 4
B -- base 4, height 4
C -- base 3, height 3
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8 0

3 years ago