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Alexxx [7]
3 years ago
10

Two points are located at (2,3) and (8,−5). Complete the equations below to show how you can use the Pythagorean theorem to find

the distance between these two points

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer:

<h2>first blank:</h2><h2>c=sqrt(a^2+b^2)</h2><h2>second blank:</h2><h2>c=sqrt((8-2)^2+(-5-3)^2)</h2><h2 />

Step-by-step explanation:

c^2=a^2+b^2

sqrt(c^2)=sqrt(a^2+b^2)

c=sqrt(a^2+b^2)

c=sqrt((x2-x1)^2+(y2-y1)^2)

c=sqrt((8-2)^2+(-5-3)^2)

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Which multiplication expression is equivalent to
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Answer:

1

Step-by-step explanation:

Correct question:  2x2 - 5x - 3 / 4x2 + 12x + 5 divided by 3x2 - 11x + 6 / 6x2 + 11x - 10.

As given: \frac{(2x^{2}-5x-3) }{(4x^{2}+12x+5 )} \div \frac{(3x^{2} -11x+6)}{(6x^{2}+11x-10) }

Solving it by using quadratic equation.

= \frac{(2x^{2}-6x+1x-3) }{(4x^{2}+10x+2x+5) } \div \frac{(3x^{2}-9x-2x+6 }{(6x^{2}+15x-4x-10) }

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \div \frac{(3x-2) (x-3)}{(2x+5) (3x-2)}

To divide fraction take the reciprocal of divisor and multiply the dividend.

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \times \frac{(2x+5) (3x-2)}{(3x-2) (x-3)}

We solve it to get 1 as it cancel fraction on both side.

Answer is 1.

5 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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