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3 years ago

If g^2 -g-6 =0 and g< 0 what is the value of -3g

Mathematics

1 answer:

jolli1 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

g^2 - g - 6 = 0 can be factored as such:

g^2 + 2g - 3g - 6 = 0

g(g + 2) - 3(g + 2) = 0

(g - 3) (g + 2) = 0

g = 3, -2

Because g must be less than 0, 3, a positive number greater than 0, cannot be used to solve "-3g". So instead we use the other solution, -2:

-3(-2) = 6, the value of -3g.

Check:

(-2)^2 - (-2) - 6 = 0

(-2)^2 - (-2) = 6

4 - (-2) = 6

4 + 2 = 6

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$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
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Answer: 1, 3, 4

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3 years ago

If g^2 -g-6 =0 and g< 0 what is the value of -3g​

If g^2 -g-6 =0 and g< 0 what is the value of -3g