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ycow [4]
3 years ago
5

Does anyone know how to do products

Mathematics
1 answer:
VikaD [51]3 years ago
5 0

Answer:

You multiply both of the numbers, and then the answer is your product

Step-by-step explanation:

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3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0
Naya [18.7K]

Answer:

<h2>x = -2 or x = 5</h2>

Step-by-step explanation:

The quadratic formula of a quadratic equation

ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}

\text{If}\ b^2-4ac

We have:

x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5

5 0
3 years ago
Which expression is equivalent to 3(6m)+m<br> 3<br> 6<br> m<br> +<br> m<br> ?
svetlana [45]

Answer:

some Equivalent expressions to 3(6m)+m is;

18m+m

6(3m)+m

2(9m)+m

19m

Step-by-step explanation:

6 0
3 years ago
7x+5+ 54 how you do this
KonstantinChe [14]

Answer:

7x+59

Step-by-step explanation:

Add 5 and 54

3 0
3 years ago
Read 2 more answers
What is the answer to this?
nekit [7.7K]

Answer:

Up

Step-by-step explanation:

Y= 1x^2 + 3x + 9

Y= Ax^2 + Bx + C

To determine which way a parabola opens just look at the coefficient (the number) of the x^2 - Always use the coefficient that is beside the x^2

So,  if the coefficient A is positive the parabola is opening upward

      if the coefficient A is negative the parabola is opening downward

7 0
2 years ago
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What is the volume of the cylinder shown below?
Anastasy [175]

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it </em><em>is </em><em>given </em><em>that</em><em>. </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>height</em><em> </em><em>of </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>base </em><em>=</em><em> </em><em>9</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>π </em><em>r^</em><em>2</em><em>h</em><em> </em><em>cubic </em><em>unit</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>now,</em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>height</em><em> and</em><em> </em><em>radius </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>in </em><em>above </em><em>formula </em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>*</em><em>9</em><em>*</em><em>9</em><em>*</em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>3</em><em>6</em><em>1</em><em>7</em><em>7</em><em>c</em><em>u</em><em>b</em><em>i</em><em>c</em><em> </em><em>unit</em>

4 0
3 years ago
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