First solve both equations
5^5+3*8
3*8=24
5^5+24
5^5= 3125
3125+24=3149
solve the second equation
13-1*12
1*12=12
13-12=1
3125 is much greater than 1 therefore 3125 > 1
put back into equation form
5^5+3*8 > 13-1*12
If there is a number before the decimal point. So one point five six (1.56) would be have a mixed number of one before the normal fractions ; 1 56/100
Answer:
if the x is supposed to be squared, the coordinates are (3,2)
39. 8 -0.7 are multiplied together so the answer is
(-0.7)^8
= 0.05765 to nearest 100 thousandth. ( using a calculator).
40. 10^4 + 0^12 = 10,000 + 0
= 10,000
y = 2 ( x + 3/4 )^2 − 25 8