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sashaice [31]
2 years ago
9

Simplify the expression. Help asap

Mathematics
2 answers:
nadezda [96]2 years ago
8 0

Answer:

{ \tt{ \frac{ {(r}^{3} ) {}^{4} }{( {r}^{3} ) {}^{8} } }} \\

» Let r³ be x:

= { \tt{ \frac{ {x}^{4} }{ {x}^{8} } }} \\

» From law of indices:

{ \boxed{ \pmb{ \green{ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{(m - n)}   }}}}

» Taking a comparison from the question;

  • a is x
  • m is 4
  • n is 8

{ \tt{ \frac{ {x}^{4} }{ {x}^{8} } =  {x}^{(4 - 8)}  }} \\  \\ { \underline{ \tt{ \:  =  {x}^{ - 4}  \: }}}

» Substitute for x as r³:

{ \tt{ = ( {r}^{3}) {}^{ - 4}   }} \\  = { \tt{( {r)}^{(3 \times  - 4)} }} \\  = { \tt{ {r}^{ - 12} }} \\  \\ { \boxed{ \mathfrak{ answer :  \: { \tt{ \red{ \:  \frac{1}{ {r}^{12} } }}}}}}

katrin [286]2 years ago
7 0

\large \mathfrak{ \frac{(r ^{3} )^{4} }{(r ^{3})^{8}  } }

Simplify the expression by multiplying exponents

\large \mathfrak{ \frac{r^{12} }{r ^{24} } }

Simplify the expression by cancelling the terms

\large \mathfrak{ \frac{1}{r ^{12} } }

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Nataly [62]

Answer:

<h3>The answer 4.2 units </h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

C(2,4) and D (5. 7)

We have

|CD|  =  \sqrt{ ({2 - 5})^{2}  +  ({4 - 7})^{2} }  \\  =  \sqrt{ ({ - 3})^{2}  + ( { - 3})^{2} }  \\  =  \sqrt{9 + 9}  \\  =  \sqrt{18}  \:  \:  \:  \:  \:  \\  = 3 \sqrt{2}  \:  \:  \:  \:  \:   \\  = 4.242640687...

We have the final answer as

<h3>4.2 units to the nearest tenth</h3>

Hope this helps you

4 0
4 years ago
Ty
Kipish [7]

Answers:

  • first box = 1
  • second box = 1
  • third box = 3
  • fourth box = 3

Refer to the graph below.

==========================================================

Explanation:

If f(x) is an even function, then f(-x) = f(x) for all x in the domain.

What this means is that we have symmetry about the y axis. We can reflect that given curve over the y axis to generate the missing left side.

The graph shows that (1,1) is on the orange curve. It reflects over to (-1,1). This means 1 goes in the first box.

Use the rule (x,y)  \to (-x,y) to apply a y axis reflection. We simply just change the sign of the x coordinate from positive to negative, while keeping the y coordinate the same.

---------------

We can also see that (3,1) is also on the orange curve. It reflects over to (-3, 1) using that rule mentioned earlier.

1 goes in the second box

---------------

The graph your teacher gave you shows that if we plugged in x = 5, then we get y = 3. In other words, the point (5,3) is on the orange graph.

It reflects over to (-5, 3) to show that x = -5 leads to the output y = 3

3 goes in the third box

----------------

Lastly, the point (6,3) reflects to (-6,3) when reflecting over the y axis.

3 goes in the fourth box.

See the graph below.

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