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jok3333 [9.3K]
3 years ago
5

Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points, to

the nearest tenth (if necessary).
(8,6) and (5,9)​
Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer: 69, -69

Step-by-step explanation:

it is easy buddy not lies

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X^3+18x−3x^2−54 Factor over complex numbers
adoni [48]

Answer:

4565

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Read 2 more answers
The formula for the future value V (in dollars) of an investment earning simple interest is V=p+prt, where p (in dollars) is the
serious [3.7K]

Answer:

A. p=\dfrac{V}{1+rt}

B. $2,307.69

Step-by-step explanation:

You are given the formula

V=p+prt,

where V = investment earning simple interest

p = principal,

r = interest rate

t = time

So,

A. V=p(1+rt)\\ \\p=\dfrac{V}{1+rt}

B. r = 0.06 (or 6% as percent)

V = $3,000

t =5

so,

3,000=p+p\cdot 0.06\cdot 5\\ \\3,000=p+0.3p\\ \\1.3p=3,000\\ \\p=\dfrac{3,000}{1.3}\approx 2,307.69

6 0
3 years ago
Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

4 0
3 years ago
Does 5 x 1,000 + 7 x 1+ 9 X 10 + 9 x 100 + 2 x 1,000 = 5,007.992
aleksandrvk [35]

Answer:

No

Step-by-step explanation:

7997

6 0
2 years ago
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