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elena55 [62]
4 years ago
7

Solve the quadratic equation.

Mathematics
1 answer:
maks197457 [2]4 years ago
7 0

Answer:

A) -3/2 and 7

Step-by-step explanation:

this equation factors to (2x+3)(x-7)

the goal is to solve for 0

if 2x+3=0 then x=-3/2

if x-7=0 then x=7

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Suppose you average 82 on your first 7 test. What must you score on the eighth test to raise your average to 84?
natima [27]

so hmmm on average on the last 7 test, you get 82, so hmmm we could say that on each of the 7 tests you got 82, so you got 82, 7 times.

now, let's say in the 8th test, you get a grade of "g", now, if we were to get an average of all 8 tests, that means the average will simply be (82*7) + "g", and we know that's 84, so

\cfrac{(\stackrel{\textit{sum of all first seven tests}}{82+82+82+82+82+82+82})~~ + ~~g}{8}~~ = ~~84\implies \cfrac{(82\cdot 7)~~ + ~~g}{8}~~ = ~~84 \\\\\\ \cfrac{574+g}{8}=84\implies 574+g=672\implies g=672-574\implies g=98

7 0
2 years ago
Read 2 more answers
What is the area of the triangle?
-Dominant- [34]

Answer:

270 centimeters squared

Step-by-step explanation:

A = H x W / 2

A = 18 x 30

A = 270

3 0
3 years ago
Read 2 more answers
HELP ASSAPPP WITH THIS QUESTION
NeTakaya
From 11 A.M. to 2 P.M. because that is when the line is constantly straight

7 0
3 years ago
Please help!!!
Goryan [66]

Answer:

64^{\circ}

Step-by-step explanation:

~~~~~~\cos \angle E = \sin \angle F\\\\\implies \cos 26^{\circ} = \sin \angle F\\ \\\implies \angle F = \sin^{-1} \left( \cos 26^{\circ} \right)\\\\\implies \angle F = \sin^{-1} \left(\sin(90^{\circ}-26^{\circ}) \right)\\\\\implies \angle F = \sin^{-1} \left( \sin 64^{\circ} \right)\\\\\implies \angle F = 64^{\circ}

8 0
2 years ago
Pls help:) i feel so guilty for asking questions
expeople1 [14]

Answer:

Step-by-step explanation:

AB:

d = sqrt ( (−5−2)^2 + (−2−(−8))^2)

d = sqrt( (−7)^2 + (6)^2  )

d = sqrt(49+36)

d = sqrt(85)

d = 9.219544

BC:

d = sqrt ( (−7−(-5))^2+(3−(−2))^2 )

d = sqrt( (−2)^2 + (5)^2  )

d = sqrt(4+25)

d = sqrt(29)

d = 5.385165

AC:

d = sqrt ( (−7−(2))^2+(3−(−8))^2 )

d = sqrt( (−9)^2 + (11)^2  )

d = sqrt(81+121)

d = sqrt(202)

d = 14.21267

DE:

d = sqrt ( (−11−(-9))^2+(12−7)^2 )

d = sqrt( (−2)^2 + (5)^2  )

d = sqrt(4+25)

d = sqrt(29)

d = 5.385165

EF:

d = sqrt ( (−2−(-11))^2+(1−12)^2 )

d = sqrt( (9)^2 + (-11)^2  )

d = sqrt(81+121)

d = sqrt(202)

d =14.21267

DF:

d = sqrt ( (−2−(-9))^2+(1−7)^2 )

d = sqrt( (7)^2 + (-6)^2  )

d = sqrt(49+36)

d = sqrt(85)

d = 9.219544

Yes, the triangles are congruent because the lengths are the same.

3 0
3 years ago
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