B: 5(x+4)^2 Explanation: The “5” at the beginning of the equation represents stretch by five (multiplying the 1, 3, 5 rule, therefore making it over one up five, over one up fifteen, etc.) the +4 represents moving right 4 times.
Answer:
try A
Step-by-step explanation:
Answer
B and A
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
i think
Given:
PQ has endpoints at P(-5, 4) and Q (7,-5).
To find:
The length of PQ.
Solution:
Distance formula:
![D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Using the distance formula, the distance between P(-5, 4) and Q (7,-5) is
![PQ=\sqrt{(7-(-5))^2+(-5-4)^2}](https://tex.z-dn.net/?f=PQ%3D%5Csqrt%7B%287-%28-5%29%29%5E2%2B%28-5-4%29%5E2%7D)
![PQ=\sqrt{(7+5)^2+(-9)^2}](https://tex.z-dn.net/?f=PQ%3D%5Csqrt%7B%287%2B5%29%5E2%2B%28-9%29%5E2%7D)
![PQ=\sqrt{(12)^2+(-9)^2}](https://tex.z-dn.net/?f=PQ%3D%5Csqrt%7B%2812%29%5E2%2B%28-9%29%5E2%7D)
![PQ=\sqrt{144+81}](https://tex.z-dn.net/?f=PQ%3D%5Csqrt%7B144%2B81%7D)
![PQ=\sqrt{225}](https://tex.z-dn.net/?f=PQ%3D%5Csqrt%7B225%7D)
![PQ=15](https://tex.z-dn.net/?f=PQ%3D15)
Therefore, the length of PQ is 15 units.