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Alex_Xolod [135]
2 years ago
14

A newsboy purchases papers at 10 cents and sells them at 15 cents. However, he is not allowed to return unsold papers. If his da

ily demand is a binomial random variable with n = 10 , p = 1 3 , approximately how many papers should he purchase so as to maximize his expected profit?

Mathematics
1 answer:
o-na [289]2 years ago
4 0

Answer: 8.700

Step-by-step explanation:

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?
sp2606 [1]

Answer:

Step-by-step explanation:

A discriminate of -8 is never going to give you a real root. D is wrong

You cannot have just 1 complex root, nor can you have just 1 real root unless the discriminate is 0. A and C are both wrong for the same reason. 1 complex root is impossible. They come in pairs.

So the answer is B. You have 2 complex roots.

7 0
2 years ago
Is these correct bro
iren [92.7K]

Answer:

yes

Step-by-step explanation:

if my eyes are good then yes

3 0
3 years ago
A sequence has three terms the term to term rule for sequence is multiple by3 and then add 7 given that the first term of the se
olasank [31]

Answer:

Step-by-step explanation:

a₁ = -1

a₂ = 3a₁ + 7 = 3(-1)+7 = 4

a₃ = 3a₂ + 7 = 3·4+7 = 19

8 0
3 years ago
A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v
BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

p_{1}=\frac{30}{120}=0.25

p_{2}=\frac{32}{160}=0.2

Second, calculate standard deviation for each proportion:

\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395

\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316

Now, we calculate standard error for difference:

SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}

SE=\sqrt{0.0395^{2}+0.0316^{2}}

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

p_{1}-p_{2} ± z-score.SE

0.25-0.2 ± 1.645(0.0505)

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = -0.0332

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is [-0.0332,0.1332].

8 0
3 years ago
Econ Question, Please use the picture below to answer. The highlighted one is my guess (might be right or wrong I don't know).
mafiozo [28]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
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