Solution :
Let us consider the squares be ![$[1, 16] \times [16, 32]$](https://tex.z-dn.net/?f=%24%5B1%2C%2016%5D%20%5Ctimes%20%5B16%2C%2032%5D%24)
If x ranges from the 0 to 16 and the y ranges from 16 to 32, we see that the boundary of the region
which goes from the 
.
And so it is easier to find the area of region where 
. This is the triangle with points 
as its vertices.
The area if the triangle is = 
= 
Now the entire area is 
= 256
Then, 
or 
Thus the answer is 
Answer: Hence, Option (6) and (8) are correct as their value is also "-8".
Step-by-step explanation:
Since we have given that
First we need to solve to get the value of 'x' :
Therefore, x=-8
Now, we will check all the options :
1) 4x+8=24
2) 9x+18=-24
3) 4x+12=-24
4) 18x+36/2=-24
5) 4x=-36
6) 4x=-32
7) x=-9
8) x=-8
Hence, Option (6) and (8) are correct as their value is also "-8".
Answer:
1.) D
2.) F
3.) C
4.) H
Step-by-step explanation:
i am positive on 4, but not totally sure on 1, 2, and 3
You dont have anything that we can answer to.
The solution of the given equation can be all real numbers, except c = 0 and c = 3.
Lets simplify the given problem,
1/c-3 - 1/c = 3/ (c-3)
As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.
Next, we would multiply both sides of the given by the lowest common multiple (LCM).
The lowest common multiple (LCM) is c(c - 3).
c-[c-3] = 3
c-c+3 = 3
0 = 3-3
0=0
Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.
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