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kykrilka [37]
3 years ago
13

How do you solve -4+3x</= -12 +5x? inequalities

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0
You were trying to write -4+3x≤12+5x

remember, you can do anything to an equaiton as long as you do it to both sides

-4+3x≤-12+5x
minus 3x both sides
-4≤-12+2x
add 12 to both sides
8≤2x
divide both sides by 2
4≤x
x≥4
x≥7.5
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Find the tangents of the acute angles in the right triangle. Write each answer as a fraction. WILL MAKE BRAINLIEST!!
patriot [66]

Answers:

  • tan(G) = 2
  • tan(H) = 1/2

=======================================

Explanation:

Recall that tangent is the ratio of opposite over adjacent

tan(angle) = opposite/adjacent

So for reference angle G, we say,

tan(G) = JH/GJ = 2/1 = 2

We'll treat tan(H) in a similar fashion, but the opposite and adjacent sides swap roles. That means we'll apply the reciprocal to the result above to get 1/2 for tan(H)

-----------

So we have this interesting property where

tan(G)*tan(H) = 2*(1/2) = 1

In general,

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Side note: The side sqrt(5) isn't used at all.

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Answer: 4/5

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