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nikklg [1K]
3 years ago
8

Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten. The rest were either ripe or unripe. There were 18 more ripe oranges

than unripe oranges. Find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.
Mathematics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

13:8:7

Step-by-step explanation:

84 - 24 = 60

60 oranges were either ripe or unripe.

18 more ripe oranges than unripe oranges.

x + 18 = ripe oranges

x = unripe oranges

x + 18 + x = 60

2x + 18 = 60

2x = 42

x = 21

21 are unripe oranges

21 + 18 = 39

39 oranges are ripe.

Ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.

39:24:21

13:8:7

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a) f(2)= 0.448 (2)^{1.21}= 1.036 grams

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Part b

For this case we know tha value for f(x) =0.5 and we want to find the value of x who satisfy this condition:

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We can appy the exponent \frac{1}{1.21} in both sides of the equation and we got:

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