Answer:
4.8 or 4 4/5
Step-by-step explanation:
You can show that
by constructing a triangle.
Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is
radians.
Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.
Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to
radians. We know one of the angles is
radians, which leaves a contribution of
radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure
radians.
Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length
, and by definition of
we have


First, we'll find the slope of the new line. The first line has a slope of
. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by
) to get
for the new slope.
Then, we'll use the point-slope form to make the new equation, where
is the slope and
is a point on the line:

The answer to this question <span>What is the sum of the first eight terms of a geometric series whose first term is 3 and whose common ratio is 1/2 is (7/65/128)</span>