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aleksandr82 [10.1K]
3 years ago
13

A 2-way light bulb for a 110 V lamp has filament that uses power at a rate of 50.0 W. What is the resistance of the filament?

Physics
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:r=242ohms

Explanation:

Power(p)=50w

Volt(v)=110v

Resistance(r)=?

Power(p)=((volt)^2)/(resistance(r))

50=110^2/r

Cross product

50xr=110^2

50r=12100

r=12100/50

r=242ohms

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user100 [1]

Answer:

Explanation:

We shall apply work energy theorem to calculate the initial velocity just after the collision .

Their kinetic energy will be equal to work done by friction .

force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity

force = .463 x 3210 x 9.8

= 14565.05 N

work done = force x displacement

= 14565.05 x 14.54 = 211775.88 J

now applying work energy theorem

1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision

.5 x 3210 x v² = 211775.88

v² = 131.94

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3 0
3 years ago
A 15kg boulder is moved from the Earth to the Moon. Explain what happens to the mass and weight of the boulder.​
elena-14-01-66 [18.8K]

Answer:

The mass of the boulder remains constant, while its weight decreases with respect to the value of gravitational force on the moon.

Explanation:

The mass of the boulder = 15 kg

On the earth, its mass remains 15 kg. But its weight is;

weight = m x g

           = 15 x 9.8

           = 147 N

The boulder's weight on the earth is 147 N.

When transferred to the moon, the mass remains constant i.e 15 kg. But its weight decreases due to a change in the value of acceleration due to gravity on the moon. Thus, the boulder becomes lighter in weight.

6 0
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Yuki888 [10]

Answer:F=3\times 10^{-5} N

Explanation:

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F'=6\times 10^{-6}

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F=3\times 10^{-5} N

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Bob's average speed was 80 m/s.

His average velocity was 40 m/s East.

The magnitude of his velocity was almost 4 times as fast as Usain Bolt's world record in the 100 meters, or about 89 mph. His speed was double that.

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Magnetic induction is used for what?
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For radio broadcasting, in electricity meters, in any generator. 
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