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Ira Lisetskai [31]
2 years ago
14

GIVING BRAINIEST TO FAST ANSWER!!!!

Physics
2 answers:
ryzh [129]2 years ago
8 0
Answer : Energy from the Sun heats the surface, warms the atmosphere, and powers the ocean currents .

So that's means the answer is the second one
Vlad [161]2 years ago
4 0

Answer:

The second one a part of it heats up Earth's land and water equally.

Explanation:

Hope this help!!!

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Are you an antisocial person. Me honestly am
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Explanation:

By the way.. What's the meaning of ANTISOCIAL??..(ㆁωㆁ)

If you tell me the meaning of it, I'll tell you my answer too(ㆁωㆁ)

7 0
3 years ago
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A man pushes a 60.8 kg crate across a rough surface with an applied force of 125 N and at a CONSTANT SPEED.
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Answer: Colby we both dumb if we need brainly lol

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4 years ago
A radioactive isotope of the element potassium decays to produce argon. If the ratio of argon to potassium is found to be 31:1,
iris [78.8K]

Answer:

Explanation:

Argon to potassium ratio after 1 half life = 1:1

After 2 half lives = 75/25= 3:1

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3 years ago
The magnitude of the electric current is directly proportional to the _____ of the electric field.
Sedbober [7]
Is proportional to the CHANGE.

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3 0
3 years ago
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Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us
nalin [4]

Answer:

13 W/m^2

Explanation:

The apparent brightness follows an inverse square law, therefore we can write:

I \propto \frac{1}{r^2}

where I is the apparent brightness and r is the distance from the Sun.

We can also rewrite the law as

\frac{I_2}{I_1}=\frac{r_1^2}{r_2^2} (1)

where in this problem, we have:

I_1 = 1300 W/m^2 apparent brightness at a distance r_1, where

r_1 = 150 million km

We want to estimate the apparent brightness at r_2, where r_2 is ten times r_1, so

r_2 = 10 r_1

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I_2 = \frac{r_1^2}{r_2^2}I_1 = \frac{r_1^2}{(10r_1)^2}(1300)=\frac{1}{100}(1300)=13 W/m^2

5 0
3 years ago
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