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Natasha2012 [34]
3 years ago
8

Bob walks to Jack's house. He walks 900 meters East then realizes that he walked too far. He turns around and walks 300 meters W

est. The entire walk takes him 15 seconds. What was his speed per second?
Physics
1 answer:
Lilit [14]3 years ago
6 0

Bob's average speed was 80 m/s.

His average velocity was 40 m/s East.

The magnitude of his velocity was almost 4 times as fast as Usain Bolt's world record in the 100 meters, or about 89 mph. His speed was double that.

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In a nuclear physics experiment, a proton (mass 1.67×10^(−27)kg, charge +e=+1.60×10^(−19)C) is fired directly at a target nucleu
Arte-miy333 [17]

The given question is incomplete. The complete question is as follows.

In a nuclear physics experiment, a proton (mass 1.67 \times 10^(-27)kg, charge +e = +1.60 \times 10^(-19) C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed 2.50 \times 10^6 m/s. The proton comes momentarily to rest at a distance 5.31 \times 10^(-13) m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are 5.31 \times 10^{-13} m apart?

Explanation:

The given data is as follows.

Mass of proton = 1.67 \times 10^{-27} kg

Charge of proton = 1.6 \times 10^{-19} C

Speed of proton = 2.50 \times 10^{6} m/s

Distance traveled = 5.31 \times 10^{-13} m

We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.

  (K.E + P.E)_{initial} = (K.E + P.E)_{final}

 (\frac{1}{2} m_{p}v^{2}_{p}) = (\frac{kq_{p}q_{t}}{r} + 0)

where,    \frac{kq_{p}q_{t}}{r} = U = Electric potential energy

     U = (\frac{1}{2}m_{p}v^{2}_{p})

Putting the given values into the above formula as follows.

        U = (\frac{1}{2}m_{p}v^{2}_{p})

            = (\frac{1}{2} \times 1.67 \times 10^{-27} \times (2.5 \times 10^{6})^{2})

            = 5.218 \times 10^{-15} J

Therefore, we can conclude that the electric potential energy of the proton and nucleus is 5.218 \times 10^{-15} J.

4 0
4 years ago
During a storm, the power went out at Bailey’s house. She had no electricity. What could she use as an alternate form of electri
almond37 [142]
A battery operated lamp because battery's don't use your own electricity. They come with electricity already.
5 0
3 years ago
Two masses sit at the top of two frictionless inclined planes that have different angles,__deleted9917f34947e1359b5705bbac0d9227
Strike441 [17]

Answer:

v = \sqrt{2gh}

the speed in the two planes will be the same since it does not depend on the angle of the same

Explanation:

In this exercise we are told that the two inclined planes have no friction force, so we can apply the conservation of energy for each one, we will assume that the initial height in the two planes is the same

starting point. Highest part of each plane

         Em₀ = U = m g h

final point. Lowest part of each plane

        Em_{f} = K = ½ m v²

as there is no friction, the mechanical energy is preserved

          Em₀ = Em_{f}

          mg h = ½ m v²

          v = \sqrt{2gh}

As we can see, the speed in the two planes will be the same since it does not depend on the angle of the same

7 0
3 years ago
An object is launched from the top of a building which is 100 m tall (relative to the ground) at a speed of 22 m/s at an angle o
klio [65]

Answer:

3.58\:\mathrm{s}

Explanation:

We can use the kinematics equation \Delta y=v_it+\frac{1}{2}at^2 to solve this problem. To find the initial vertical velocity, find the vertical component of the object's initial velocity using basic trigonometry for right triangles:

\sin28^{\circ}=\frac{y}{22},\\y=22\sin28^{\circ}=10.3283743813\:\mathrm{m/s}

Now we can substitute values in our kinematics equation:

  • \Delta y=-100
  • a=-9.8\:\mathrm{m/s^2} (acceleration due to gravity)
  • v_i=-10.3283743813\:\mathrm{m/s}
  • Solving for t

-100=-10.3283743813t+\frac{1}{2}\cdot -9.8\cdot t^2,\\\\-4.9t^2-10.3283743813t+100=0,\\\\\boxed{t=3.5849312673637455}, t=-5.692762773751501\:\text{(Extraneous)}

6 0
3 years ago
How is an experiment is actually conducted
NeX [460]
By using the scientific method
3 0
3 years ago
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