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Anna71 [15]
4 years ago
7

In general it is expected that ________. A) osmotic pressure will remain relatively consistent throughout the capillary bed B) o

smotic pressure will be lower in the arteriole end of the capillary bed compared to the venous end C) osmotic pressure will be higher in the arteriole end of the capillary bed compared to the venous end D) hydrostatic pressure will remain constant throughout the capillary bed
Physics
1 answer:
Tanya [424]4 years ago
7 0

Answer:

B. OSMOTIC PRESSURE WILL BE LOWER IN THE ARTERIOLE END OF THE CAPPILLARY BED COMPARED TO THE VENOUS END.

Explanation:

This is true for filtration to take place in the cappillary bed. Osmotic pressure is the net pressure that drives movement of fluid from the interstitial fluid back into the capillaries. Osmotic pressure increase favors reabsorption as water moves from region of higher water concentration in the interstitial fluid to the lower region of water concentration in the capillaries.

At the ends of a capillary bed, the difference in the hydrostatic and osmotic pressures provides a net filtration or reabsorption ratio. At the arteriole end of the capillary bed, hydrostatic pressure is greater than the osmotic pressure allowing movements of fluid to the interstitial fluid (filtration) while as the blood moves to the venous end, the osmotic pressure becomes greater than than hydrostatic pressure.

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Answer:

2.49 seconds

Explanation:

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a = (v-u)/t............................ Equation 1

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Make t the subject of the equation

t = (v-u)/a.......................... Equation 2

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t = (6.5-11)/(-1.81)

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t = 2.49 s

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7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
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Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

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Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

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Read 2 more answers
Convert: Thermal conductivity value of 0.3 Btu/(h ft°F) to W/(m °C). Surface heat transfer coefficient value of 105 Btu/(h ft2 o
Finger [1]

Answer:

0.3 Btu/(h ft °F) = 0.5189 W/(m°C)

105 Btu/(h ft² °F) = 596.2215 W/(m²°C)

Explanation:

<u>Thermal conductivity of a substance is defined as the measure of the tendency of the substance to conduct heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻¹K⁻¹ .</u>

From the question , 0.3 Btu/(h ft °F) is to be converted to W/(m°C)

Thus,

1 Btu/(h ft °F) = 1.7296 W/(m°C)

So,

0.3 Btu/(h ft °F) = 1.7296×0.3 W/(m°C) = 0.5189 W/(m°C)

Thus,

<u>0.3 Btu/(h ft °F) = 0.5189 W/(m°C)</u>

<u>Heat transfer coefficient is defined as proportionality constant between heat flux (Thermal power per unit area) and the temperature difference of the substance for that flow of heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻²K⁻¹ .</u>

From the question , 105 Btu/(h ft² °F) is to be converted to W/(m²°C)

Thus,

1 Btu/(h ft² °F) = 5.6783 W/(m²°C)

So,

105 Btu/(h ft² °F) = 5.6783×105 W/(m²°C) = 596.2215 W/(m²°C)

Thus,

<u>105 Btu/(h ft² °F) = 596.2215 W/(m²°C)</u>

3 0
3 years ago
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