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3 years ago

8

One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I

2=0.75 Amps. They are 5 meters long in this configuration and separated from each other by 5 cm. What is the magnitude of the force experienced by the wire carried I2?

1 answer:

Yuki888 [10]3 years ago

6 0

Answer: $F=3\times 10^{-5} N$

Explanation:

Given

$I_1=2 Amps$

$I_2=0.75 Amps$

Length of each wires $\left ( L\right )=5 m$

Distance between wires $\left ( r\right )=5 cm$

Force per unit length = $\frac{\mu_0I_1I_2}{2\pi r}$

$F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}$

$F'=6\times 10^{-6}$

Force for $L=5 m$

$F=3\times 10^{-5} N$

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