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Wittaler [7]
2 years ago
8

One wire carries a current of I1= 2 Amps, and the other carries a parallel current (same direction, wires are side by side) of I

2=0.75 Amps. They are 5 meters long in this configuration and separated from each other by 5 cm. What is the magnitude of the force experienced by the wire carried I2?
Physics
1 answer:
Yuki888 [10]2 years ago
6 0

Answer:F=3\times 10^{-5} N

Explanation:

Given

I_1=2 Amps

I_2=0.75 Amps

Length of each wires\left ( L\right )=5 m

Distance between wires \left ( r\right )=5 cm

Force per unit length =\frac{\mu_0I_1I_2}{2\pi r}

F'=\frac{2\times 10^{-7}\times 2\times 0.75}{2\pi \times 0.05}

F'=6\times 10^{-6}

Force for L=5 m

F=3\times 10^{-5} N

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<h3>Current </h3>

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Hope this explanation was helpful and brief! :)
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